Square root of perfect squares. This chapter illustrates how to calculate the square root of a perfect square. For example, 142 = 196 so
Table of basic squares 1 to 10 must me memorized:
12 = 1
22 = 4
32 = 9
42 = 16
52 = 25
62 = 36
72 = 49
82 = 64
92 = 81
102 = 100
From this table we can determine the calculation between unit digit of a square and its square root.
Unit Digits Of
Square Square root
Now it can be seen clearly that except for 5 and 0 the relationship between the unit digits of square and square root is not unique, so we get 2 possible unit digits for each unit digit of a perfect square
Note : A perfect square CAN NOT end in 2, 3, 7 or 8 as these digits are not appearing as unit digits of a perfect square
Example :- Now if we want to calculate square root of 4096
Step 1: Write the unit digits as 4 or 6
Step 2: Remove 2 digits from the right of the no.
Step 3: Now refer the remaining no. (40) to the basic square table, 40 lies between 62 and 72 (62 < 40 < 72)
Step 4: Select smaller square (6) for the ten’s digit of square root
Now we still have two possible answers
64 or 66
So how do we resolve this issue? We need to take the assistance of the middle number 65 which lies between 64 and 66
652 = (6 x 7) / 52
= 4225 (By Ekadhikena-purvena.)
Now by comparing 4096 with 4225
4096 < 4225
Since 4096 is less than 4225 its square root should also be the square root of 4225 (which is 65)
Hence 64 < 65
So the final answer is 64 and not 66.
Example 2
Unit digit 1 or 9 (corresponding to 1)
Ten’s digit is 4 as 42 < 24 < 52
So possible answers are 41 or 49
Square of middle no 452 = 2025
As 2401 > 2025
so
49 > 45
So final answer is 49 and not 41
Example 3:
Example 4:
Example 5:
Example 6:
Exercises:
Now if the square consists of a 5 digit or a 6 digit number then its square root will have 3 digits
Example:
Step 1: Unit digit will be either 4 or 6
Step 2: Remove 2 digits from the right side of the number.
Step 3: 102 < 108 < 112
So now we have two possible answers 104 or 106
Take the middle no: 105
Compare
Select 104 as final answer
Exercises:
Course: